3x^2+15-2x=(x^2+5)-2x

Solution for 3x^2+15-2x=(x^2+5)-2x equation:

3x^2+15-2x=(x^2+5)-2x

We move all terms to the left:

3x^2+15-2x-((x^2+5)-2x)=0


We calculate terms in parentheses: -((x^2+5)-2x), so:

(x^2+5)-2x

We add all the numbers together, and all the variables

-2x+(x^2+5)

We get rid of parentheses

x^2-2x+5

Back to the equation:

-(x^2-2x+5)


We get rid of parentheses

3x^2-x^2-2x+2x-5+15=0

We add all the numbers together, and all the variables

2x^2+10=0

a = 2; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·2·10
Δ = -80
Delta is less than zero, so there is no solution for the equation